Four consecutive even integers have a sum of –156. What is the least of these integers?
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Let us assume three consecutive numbers of series be x,x+1 and x+2
So, the sum of these consecutive numbers = x+x+1+x+2=156
⇒3x+3=156
⇒3x=156−3
⇒3x=153
⇒x=51
Three consecutive odd numbers = x,x+1 and x+2
x=51
x+1=51+1=52
x+2=51+2=53
Therefore, among the three, 51 is the multiple of 3.
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