Question

Four consecutive even integers have a sum of 252

Answer 1

Answer:

let 1at consecutive integer be X

2Nd consecutive integer be X+2

3rd --- X+4

and 4th। X+6

by the qnn

X + X+2 +X+4 +X+6=252

Answer 2

$\huge\star\underline{\mathtt\red{a}\mathtt\green{N}\mathtt\blue{s}\mathtt\purple{W}\mathtt\orange{e}\mathtt\pink{R}}\star\:$

Let us call x the smallest integer. Because the next two numbers are consecutive even integers, we can call represent them as x + 2 and x + 4. We are told the sum of x, x+2, and x+4 is equal to 72.