Question

Four consecutive even integers have a sum of 340. What is the least of the 4 integers?

Answer 1

Answer:

Step-by-step explanation:

LET X BE THE FIRST INTEGER.

X+2, X+4, X+6 BE THE SUBSEQUENT INTEGERS.  

X+(X+2)+(X+4)+(X+6)=340

4X+12=340

4X=340-12

4X=328

X=328/4

X=82 FOR TRHE SMALLEST INTEGER.

82+2=84 FOR THE NEXT INTEGER.

82+4=86 FOR THE NEXT INTEGER.

82+6=88 FOR THE LARGEST INTEGER.