Question

Four consecutive integers are such that the sum of the 2nd and 4th integers is 132. What are the four integers?

Answer 1

X, X+1, X+2, X+3

X+1+X+3=132

2X+4=132

2X=132-4

2X=128

X=128/2

X=64

X+1=64+1=65 ANSWER FOR THE SMALLER NUMBER.

X+3=64+3=67 ANSWER FOR THE LARGER NUMBER.

PROOF

65+67=132

132=132

Answer 2

let the integers be

a-3d ,a-d ,a+d ,a+3d

Now as given

a-d+a+d =132

2a =66

a=33

Hence numbers are