Question

Four consecutive integers have a sum of 342.

Answer 1

let the numbers be x, x+1, x+2, x+3
sum of the numbers=342
x+x+1+x+2+x+3=342
4x+6=342
4x=342-6=336
x=336/4
x=84
the numbers are 84, 85, 86 and 87

Answer 2

The four numbers are "83.25", "84.25", "85.25" and "86.25".

Step-by-step explanation:

$Let \ the \ four \ consecutive \ number \ be,\\x,(x+1),(x+2) \ and \ (x+3)\\Their \ sum=342\\According \ to \ the \ question,\\x+x+2+x+3+x+4=342\\4x+9=342\\On \ subtracting \ "9" \ from \ both \ sides,we \ get\\4x+9-9=342-9\\4x=333\\x=\frac{333}{4}\\x= 83.25\\So, the \ first \ number=83.25\\Second \ number=83.25+1=84.25\\Third \ number=84.25+1=85.25\\Fourth \ number=85.25+1=86.25$

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