Four consecutive number whose sum is 18 are _____,____,____,_____.
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Hence there there is no 4 consecutive odd integers with sumof 18. Let, numbers are (2a-3) , (2a-1) , (2a+1) , (2a+3). Numbers are : 1•5 , 3•5 , 5•5 , 7•5 . (2n+1)+(2n+3)+(2n+5)+(2n+7)=18;8n+16=18; 8n=2; n=2/8=1/4=0,25.
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Answer:
Shortcut method
Sum of three consecutive number = 18
shortcut = 18-3/3
= 15/3 = 5
Therfore the numbers are 5,6,7
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