Question

Four consecutive positive integers have a sum of 802. Column a column b the least of the four integers 199

Answer 1

Answer:

The four consecutive integers are 199, 200, 201,202

Step-by-step explanation:

Let the four consecutive integers be x, +1, x+2, x+3

Given:

Their sum = 802

x+(x+1)+(x+2)+(x+3)=802

4x+6=802

4x=802-6

4x=796

$x=\frac{796}{199}$

$\implies\:x=199$

The four consecutive integers are 199, 200, 201,202