Math, asked by vijayaranisolipeta78, 3 months ago

Four consecutive terms of an arithmetic sequence are z, 2.x, 2y, and r-y+12.
What is the ninetieth term of that sequence?​

Answers

Answered by anittajoseph911
3

Answer:

2y = 4x-8, or

y = 2x-4 …(1)

2x, 2y and 36 form a GP, or

36/2y or 18/y = 2y/2x or y/x

y^2 = 18x …(2)

Equate (1) and (2)

(2x-4)^2 =18x.

4x^2–16x+16 = 18, or

4x^2–34x+16 = 0

2x^2–17x+8 = 0

(2x-1)(x-8) = 0

x= 1/2 or 8

y = -3 or 12

Check: 8, 2x, 2y become 8, 1, -6. Correct as an AP.

2x, 2y, 36 become 1, -6, 36. Correct as an GP.

8, 2x, 2y become 8, 16, 24. Correct as an AP.

2x, 2y, 36 become 16, 24, 36. Correct as an GP.

x= 1/2 and y = -3, or

x = 8 and y = 12.


vijayaranisolipeta78: it is wrong
anittajoseph911: no way hamra school ma liya tha
vijayaranisolipeta78: no the answer is 48
anittajoseph911: no
Answered by somvanshiabhijeetsin
0

This is easy, I remember this one from Day School when I was pounding the Square Peg into the Round Hole with a Rubber Mallot. Because ANY sequence MUST comprehend as part of Why Newton debated: For theory of everything up is also a theory of everything down, to come to his latter publications, Atwhich: Meeting a criterium of that.

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