Question

four cows are tethered at four corners of a square plot of side 70 m with ropes of length 35 metres. the minimum area left ungrazed is​

Answer 1

area of square = area of 4 sectors 

then the next step will be the following,

the remained ungrazed cows 

radius or in short form as (r) = 70/2 which is = 35 

because in 2 table 70 goes at 35 and 35 * 2 = 70

now the tell us see the (side)² r - 0/360 × πr²

symbolicaly it will be

(70)² - 4 × 90/360 × 35 × 35

the canceled numbers are below they are:

7 and 35 cancels and 35 becomes into 5 and 7 becomes 1

0 and 0 cancels 

and 9 and 36 cancels and 9 becomes 1 and 36 as 4

4 and 4 cancels and becomes 1

so,the remaining numbers are 5 and 35 

so,we should multiply 35 and 5

in a symbolical way it will be 

35 × 5 

now 4990 - 3850

in a symbolical way

4990 - 3850 = 1050cm²

the answer is 1050cm²

thank you this was an hardwork to me to post directly 

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Answer 2

Step-by-step explanation:

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