Four cows are tethered at four corners of a square plot of side 50 m, so that they just cannot reach one another. What area will be left ungrazed?
Answers
Answer:
The area left ungrazed will be 535.71 m² .
Step-by-step explanation:
Given :
Side of a square plot, ABCD = 50 m
Radius of quadrant = 25 cm
Area of square, A1 = side ²
A1 = 50 × 50
A1 = 2500 cm²
Area of square = 2500 cm²
Area of quadrant,A2 = ¼ πr²
A2 = ¼ × π× 25²
A2 = 625π/4
A2 = 625 × 22/7 × 1/4
A2 = 625 × 11 × 1/7 × 1/2
A2 = 6875/14
A2 = 491.07 m²
Area of quadrant = 491.07 m²
Area left ungrazed = Area of shaded region
Area of shaded region, A = Area of a square - 4 × Area of quadrant
A = A1 - 4 × A2
A = 2500 - 4× 491.07
A = 2500- 1964.28
A = 535.71 m²
Area of shaded region = 535.71 m²
Hence, the area left ungrazed will be 535.71 m² .
HOPE THIS ANSWER WILL HELP YOU….
Here are more questions of the same chapter :
In the following figure, PQRS is a square of side 4 cm. Find the area of the shaded square.
https://brainly.in/question/9475522
A square water tank has its side equal to 40 m. There are four semi-circular grassy plots all round it. Find the cost of turfing the plot at Rs. 1.25 per square metre (Take π = 3.14).
https://brainly.in/question/9470130
area of square = 50×50
=2500m^2
area of 4 quadrants = 4×πr^2/4
= πr^2
=22/7×25×25
= 1,964.28m
Area left ungrazed = 2500-1964.28
= 535.72 m