Question

four cubes each of side 5 cm are joined end to end . find surface area of the resultant cubiod

Answer 1

length of the cuboid formed = 10 cm
breadth of the cuboid formed = 10 cm
depth of the cuboid = 5 cm
surface area of a cuboid = 2 × [l×b + b×h + l×h]
= 2 × [10×10 + 10×5 + 10×5]
= 2 × [100 + 50 + 50]
= 2 × [ 200]
= 400 cm^2

Answer 2

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