four cubes each of side 5 cm are joined end to end find the surface area resulting cuboid
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Given, each side of the cube is 5 cm.
When three cubes are joined end to end, then the resulting solid is a cuboid.
Length of the cuboid, l = 2 × each side of the cube = 2 × 5 cm = 10 cm
Breadth of the cuboid, b = each side of the cube = 5 cm
Height of the cuboid, h = each side of the cube = 5 cm
Surface area of the cuboid
= 2 (lb + bh + hl)
= 2 (10 cm × 5 cm + 5 cm × 5 cm + 5 cm × 10cm)
= 2 (50 cm² + 25cm² + 50 cm²)
= 2 × 125 cm².
= 250 cm².
Thus, the surface area of the resulting cuboid is 250 cm².
When three cubes are joined end to end, then the resulting solid is a cuboid.
Length of the cuboid, l = 2 × each side of the cube = 2 × 5 cm = 10 cm
Breadth of the cuboid, b = each side of the cube = 5 cm
Height of the cuboid, h = each side of the cube = 5 cm
Surface area of the cuboid
= 2 (lb + bh + hl)
= 2 (10 cm × 5 cm + 5 cm × 5 cm + 5 cm × 10cm)
= 2 (50 cm² + 25cm² + 50 cm²)
= 2 × 125 cm².
= 250 cm².
Thus, the surface area of the resulting cuboid is 250 cm².
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