Four cubes each of side 5cm are joined end to end . find surface area of resultant cuboid...........please answer fast.
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Given,
the side of a cube = 5
the four cube each of side 5cm are joined to end and form a cuboid
we have to find the surface area of cuboid
we know that ,
surface area of cuboid is 2 ( lb+ bh + hl)
here,
breath (b)= 5cm
height (h) =5 cm
length (l) = 5+5+5+5= 20 cm
therefore surface area of cuboid = 2( 20×5+5×5+5×20)
= 325 sq cm
the side of a cube = 5
the four cube each of side 5cm are joined to end and form a cuboid
we have to find the surface area of cuboid
we know that ,
surface area of cuboid is 2 ( lb+ bh + hl)
here,
breath (b)= 5cm
height (h) =5 cm
length (l) = 5+5+5+5= 20 cm
therefore surface area of cuboid = 2( 20×5+5×5+5×20)
= 325 sq cm
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