Four cubes of edges 5 cm. each are placed side by side and stuck together if the outer surface alone is painted at 300 rs. per meter square find the cost of painting
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If two cubes are joined, then the resultant shape will be a cuboid and the length of that cuboid will be twice the edge of each cube,breadth and height are the edge of cube.
Therefore,the length of the cuboid(l)=2*5=10cm
Breadth of the cuboid(b)=5cm
Height of the cuboid(h)=5cm
Total surface area of the cuboid=2[lb+bh+lh]
=2[(10*5)+(5*5)+(10*5)]
=2(50+25+50)
=2(125)
=250 sq.cm.
Cost of painting=250(300)=Rs.75,000.
Answer may help.
Therefore,the length of the cuboid(l)=2*5=10cm
Breadth of the cuboid(b)=5cm
Height of the cuboid(h)=5cm
Total surface area of the cuboid=2[lb+bh+lh]
=2[(10*5)+(5*5)+(10*5)]
=2(50+25+50)
=2(125)
=250 sq.cm.
Cost of painting=250(300)=Rs.75,000.
Answer may help.
Answered by
3
It s answer will be 75000
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