Four cubes of edges 5 cm each is placed side by side and stuck together. If the outer surface alone is painted at rupees 300/sq.m, find the cost of painting.
Answers
Step-by-step explanation:
four cubes means that the length will increase.
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cm
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface area
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)=2(100+100+25)
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)=2(100+100+25)=2 * 225
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)=2(100+100+25)=2 * 225=450 sq. cm
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)=2(100+100+25)=2 * 225=450 sq. cm10000 sq.cm = 1sq.m
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)=2(100+100+25)=2 * 225=450 sq. cm10000 sq.cm = 1sq.m450 sq.cm = 0.045sq.m
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)=2(100+100+25)=2 * 225=450 sq. cm10000 sq.cm = 1sq.m450 sq.cm = 0.045sq.mcost of painting= 300 * 0.045
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)=2(100+100+25)=2 * 225=450 sq. cm10000 sq.cm = 1sq.m450 sq.cm = 0.045sq.mcost of painting= 300 * 0.045= Rs 13.5
four cubes means that the length will increase.thus length=(5+5+5+5)= 20cm, breadth= 5cm, height= 5cmtherefore it forms a cuboid. we need to find the TSA or the total surface areaTSA of a cuboid = 2(lb+lh+bh)=2(20 * 5 + 20 * 5 + 5 * 5)=2(100+100+25)=2 * 225=450 sq. cm10000 sq.cm = 1sq.m450 sq.cm = 0.045sq.mcost of painting= 300 * 0.045= Rs 13.5
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