Question

Four cylinders of volume 4L, 3L, 2L, 1L of He, Cl2, CO2, NH3, then the ratio of number of atoms:
a. 1:3:3:1
b. 1:2:3:4
c. 1:1:2:2
d. 4:3:2:1

with explanation please....thanks

Answer 1

Answer:

Option D

No of atons = given volume / 22.4 L

Substitute

And ratio will be 4:3:2:1

Answer 2

Answer:

The ratio of the number of atoms for He, Cl₂, CO₂, NH₃ will be 1:3:3:1.

Explanation:

As we know that

For any gas 22.4 liters  of gas at STP = 1mole$=N_{A}$ molecules

where $N_{A}$ is Avogadro number.

No. of atoms in 1 mole gas = No. of atoms in molecular formula $*N_{A}$            

For 4L of He no. of atoms $=\frac{4}{22.4}N_{A}$

For 3L of Cl₂ no. of atoms $=\frac{6}{22.4}N_{A}$

For 2L of CO₂ no. of atoms $=\frac{6}{22.4}N_{A}$

For 1L of NH₃ no. of atoms$=\frac{4}{22.4}N_{A}$

By putting them together,

           $\frac{4}{22.4}N_{A}:\frac{6}{22.4}N_{A}:\frac{6}{22.4}N_{A}:\frac{4}{22.4}N_{A}$

Multiple by $\frac{22.4}{N_{A}}$:

                          $4:6:6:4$

We will get ratio,

   ⇒                     $1:3:3:1$