Question

Four defective bulbs are accidently mixed with six good ones. If it is not possible to just

look at a bulb and tell whether or not it is defective, find the probability distribution of

the number of defective bulbs, if four bulbs are drawn at random from this lot.​

Answer 1

Answer:

i don't know the answer

Answer 2

P(Good bulbs) =6/10

                        =3/5

P(defective) =4/10

                    =2/5

Variable no. can be=0,1,2,3,4

P(X=0)

       = 4C0 6/10 x 5/9 x 4/8 x 3/7

       =1/14

P(X=1)

       = 4C1 x 4/10 x 6/9 x 5/8 x 4/7

       = 8/21

P(X=2)

       = 4C2 x 4/10 x 3/9 x 6/8 x 5/7

       = 3/7

P(X=3)

       = 4C3 x 4/10 x 3/9 x 2/8 x 6/7

       = 4/35

P(X=4)

        = 4C4 x 4/10 x 3/9 x 2/8 x 1/7

         1/210

This is my little effort to help you!

Really not very sure about the answer!! If right, good enough, if not please try correcting me!!