Question

Four dice are rolled. The number of possible outcomes in which at least one dice show 2 is
(a) 1296
(b) 671
(c) 625
(d) 585​

Answer 1

Total Possible outcomes when 4 dice are rolled = 6⁴. Total Possible outcomes where none of the dice shows 2 = 5⁴. = 671.

(a) 1296

$\rm\underline\bold{(b)671 \red{\huge{\checkmark}}}$

(c) 625

(d) 585

Answer 2

Answer:

$\huge\pink{AnSwer}$

(b) 671

Explanation:-

No. of ways in which any number appearing in one dice = 6

No. of ways in which 2 appear in one dice = 1

No. of ways in which 2 does not appear in one dice = 5

There are 4 dice.

Getting 2 in at least one dice = Getting any number in all the 4 dice – Getting not 2 in any of the 4 dice.

= (6×6×6×6) – (5×5×5×5)

= 1296 – 625

= 671