Question

four dice are rolled together. What is the probability as getting at least one '5'?

Answer 1

Answer:

13/108

Step-by-step explanation:

The possible outcomes are:

P(1 five) = 1/6 x (5/6)^3 = 125/1296

P(2 fives) = (1/6)^2 x (5/6)^2 = 25/1296

P(3 fives) = (1/6)^3 x (5/6) = 5/1296

P(4 fives) = (1/6)^4 = 1/1296

P (>= 1 five) = (125 + 25 + 5 + 1) / 1296

P (>= 1 five) = 156/1296 = 13/108