Question

Four different numbers are given. Average of the first three numbers

Is four times the number and the average of all four numbers is 52. What is the average of the first three numbers?​

Answer 1

Answer:

Although the complete question is missing, I will try my best to help you.

Step-by-step explanation:

Let given numbers be a, b, c and d.

Given, (a+b+c+d)/4 = 52

=> a+b+c+d = 52*4                          ....(i)

Also given, (a+b+c)/3 = 4d

=> a+b+c = 12d

So, a+b+c+d = 12d + d = 13d           ....(ii)

Solving (i) and (ii), we get, d=16

So, in equation (i),

a+b+c+16 = 52*4

a+b+c = 208-16 = 192

(a+b+c)/3 = 192/3 = 64

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