Chemistry, asked by s7at7ankamvara, 1 year ago

Four elements A, B, C, D are given ; A shows the presence of 20 Neutrons, 17 Protons and 17 Electrons. B shows the presence of 18 Neutrons, 17 Protons and 17 Electrons. C shows the presence of 10 Neutrons, 9 Protons and 10 Electrons. D shows the presence of 04 Neutrons, 03 Protons and 02 Electrons. State which of the above is - a) an anion b) a cation, c) a pair of isotopes. Write the formula of the compound formed between D and C

Answers

Answered by ttanvi603
8

Answer:

Explanation:

C is an anion (10 electrons and 9 protons)

D is a cation (2 electrons and 3 protons)

A and B are istopes (both having 17 protons)

formula between c and d will be CD

Answered by qwmagpies
7

a) The anion is C.

b) The cation is D.

c) A and B are the isotopes.

The formula of the compound is LiF.

  • The species which contain electrons more than protons are anions. Hence the anion is C.
  • The species which contain electrons less than protons are cations. Hence the cation is D.
  • The species which contains the same number of protons but a different number of neutrons is called an isotope. Hence A and B are isotopes.
  • C is fluoride ion and D is Li-ion. Hence the formula of the compound is LiF.
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