Question

four equal circles are drawn at the four corners of a square of sides 28 cm such that each touches two other circles find the area of the square not enclosed by four circles​

Answer 1

1. find area of square
2. Find one area of sector.
3. then subtract equation 1 and 2 you will get area of square not include

Answer 2

Answer:

168 sq. cm.

Step-by-step explanation:

Refer to the above Diagram for convenience...

Side of the Square: 28cm.

Area of the Square:

${s}^{2}$

${28}^{2}$

$784 \: {cm}^{2}$

Radius of the Circle:

$\frac{28}{2}$

$14 \: cm$

{In the diagram, we get the circles enclosed by the Square forms 4 quater circles...}

Area of each quater circle:

$\frac{\pi {r}^{2} }{4}$

$\frac{22 \times 14 \times 14}{7 \times 4}$

$\frac{616}{4} {cm}^{2}$

$154 {cm}^{2}$

Number of quater circles: 4

Area of all quater circles:

$154 \times 4$

$= 616 {cm}^{2}$

Area of square not enclosed by the circles:

$784 - 616$

$168 {cm}^{2}$

Hence, the area of square not enclosed by the circles is 168 sq.cm.

Hope it helped you...

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