four equal circles are drawn at the four corners of a square of side 28 cm such that,each touches two other circles .find the area of square, not enclosed by the four circles.
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area of square = 28×28 = 784 cm^2
area enclosed by a quarter circle = 1/4 × πr^2
area enclosed by 4 quarter circles = 4×1/4×πr^2 = πr^2 = 22/7 × 14^2 =616 cm^2
area of square, not enclosed by the four circles = 784 -616 = 168 cm^2
area enclosed by a quarter circle = 1/4 × πr^2
area enclosed by 4 quarter circles = 4×1/4×πr^2 = πr^2 = 22/7 × 14^2 =616 cm^2
area of square, not enclosed by the four circles = 784 -616 = 168 cm^2
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