Question

four equal circles are drawn at the four corners of a square of side 28 cm such that,each touches two other circles .find the area of square, not enclosed by the four circles.

Answer 1

hi friend
here's your answer looking for

here,

the radius of circle is 14cm

so,

Area of 1/4 circle =
$\frac{1}{4} (\pi {r) }^{2} \\ \frac{1}{4} \times \frac{22}{7} \times 14 \times 14 \\ = 154 {cm}^{2}$
so, here is four 1/4 circle
so, let's find the area of 4 such circle

$154 \times 4 \\ = 616 {cm}^{2}$
now, area of squares
$= side \times side \\ = 784 {cm}^{2}$
now , area of figure that is not enclosed by circle is
$784 - 616 \\ = 168 {cm}^{2}$
hope you are satisfied with my answer