Four equal circles, each of radius a units, touch each other.Show that the area between them is (6/7 a2) sq.Units.
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Answer:
Area between circles is 6/7 a².
Step-by-step explanation:
Let circles be with centres A, B, C, D
Join A, B, C and D then ABCD is square formed with side = (a + a) = 2a
Radius = a
Area between circles = area of square – 4(area of quadrant)
(shaded region)
= (2a)²−4(1/4 area of circle with radius ′a′)
= 4a²- 4 (1/4)× a²
= a² (4-π)
= a² ( 4-22/7)
= (28-22/7)a²
= 6/7 a².
∴ Area between circles is 6/7 a².
i hope it will helps you friend
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