Question

four equal positive charge 16 microcoulomb placed at the four corner of square of side 0.2m . calculate net force on anyone of the charge​

Answer 1

Answer:

Explanation:

Let ABCD is square of side length 0.2m and four equal point charge each of 16 micro coulomb are placed on the four corner A, B, C and D of the square.

we have to find force experienced by anyone of the charge . we take point A, we have to find force experienced by point A.

to understand see diagram,

force exerted by B on A = Kq²/a²

where q = 16 microcoulomb, a = 0.2m

force exerted by C on A = Kq²/(√2a)² = Kq²/2a²

force exerted by D on A = Kq²/a²

now, resultant of force exerted by B and D on A = √{(Kq²/a²)² + (Kq²/a²)²}= √2Kq²/a² , it is along CA .

now, net force experienced by A = resultant of force exerted by B and D on A + force exerted by C on A

= √2Kq²/a² + Kq²/2a²

= (√2 + 1/2)Kq²/a²

= (2√2 + 1)Kq²/2a²

now, putting k = 9 × 10^9 Nm²/C² , q = 16 × 10^-6 C and a = 0.2 m

= (2√2 + 1) × 9 × 10^9 × (16 × 10^-16)²/2(0.2)²

= (2√2 + 1) × 9 × 256 × 10^-3/(0.08)

= (2√2 + 1) × 9 × 32 × 10^-1

= 110.258 N along CA