Question

four equal resistors are connected in series with a 4 volt battery then 0.5 A current flows in circuit.Find the value of each resistor

Answer 1

Explanation:

Let four resistor R1 = R2 = R3 = R4 = k

V = 4 volt

I = 0.5 A

V = I×R1 + I×R2+ I×R3 + I×R4 = i(R1 + R2 + R3 + R4)

V = i × 4k

4k = $\frac{V}{I}$

k = $\frac{V} {4 \times I}$

= $\frac{5} {4\times 0.5 A}$

= $\frac{5 volt} {2 A}$

= 2. 5 ohm

The value of each resistor is 2. 5 ohm.