Question

Four faradays of electricity were passed through AgNO,(l), Cdso(l), AICI? (C) and PbCl4() kept in four
vessels using inert electrodes. The ratio of moles of Ag, Cd, Al and Pb deposited will be
(1) 12:4:6:3
(2) 1:2:3:4
(3) 12:6:4:3
(4) 4:3 2:1​

Answer 1

Explanation:

Four faradays of electricity were passed through AgNO,(l), Cdso(l), AICI? (C) and PbCl4() kept in four

vessels using inert electrodes. The ratio of moles of Ag, Cd, Al and Pb deposited will be

(1) 12:4:6:3

(2) 1:2:3:4✔️✔️

(3) 12:6:4:3

(4) 4:3 2:1

Answer 2

The ratio of moles of Ag, Cd, Al and Pb deposited will be 12:6:4:3.

• One mole Ag(+) requires one faraday charge for reduction , so 4 faradays of charge will deposit 4 moles of Ag.

• One mole Cd(2+) requires two faraday charge for reduction , so 4 faradays of charge will deposit 2 moles of Cd.

• One mole Al(3+) requires one faraday charge for reduction , so 4 faradays of charge will deposit 4/3 moles of Al.

• One mole Pb(4+) requires one faraday charge for reduction , so 4 faradays of charge will deposit 1 mole of Pb.
• Therefore ratio =4:2:4/3:1(multiplying by 3)

                                  =12:6:4:3