Question

Four-fifths of an alloy (which is a mixture of metals) is iron. The rest is copper. How much copper (in kg) will 6 3/4 kg of the alloy contain?

Answer 1

Answer:

$6\frac{3}{4}$ kg of alloy will contain $1\frac{7}{20} kg$ of copper.

Step-by-step explanation:

Given that, $\frac{4}{5}$th of an alloy is iron.

The rest is copper.  

Then part of copper is $(1 - \frac{4}{5} )$th of the alloy = $\frac{1}{5}$th of the alloy.

Therefor, $6\frac{3}{4}$ kg of alloy will contain $\frac{1}{5} . \frac{(6).(4) + 3}{4}$ kg of copper.

$=\frac{1}{5} . \frac{27}{4} kg = \frac{27}{20} kg=1\frac{7}{20} kg$ of copper.

Answer 2

Answer:

Answer is 1  7/20

Step-by-step explanation:

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