Four forces P,2P,3P and 4P act along sides of a ssquare taken in order,their resultant is:-
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Hi friend,
oh my god..... made the biggest mistake ever......so sorry...... I know how to solve this question...... didn't noticed the question properly....... sorry
see it's easy...
as if I have already answered the question i can't send u the picture where I have solved it....
make a square marked with P,2P,3P and 4P in order
now u can see that 2P and 4P are directed in opposite direction so there resultant will be 2P and u can even see that P and 3P are in opposite direction their resultant will be 2P as well
now ,
the angle between 2P vector and 2P vector is π/2
so there resultant will be 2√2P
by using,
R = √2P²+2P² + 4P²cos90°
R = √8P²
R= 2√2P
oh my god..... made the biggest mistake ever......so sorry...... I know how to solve this question...... didn't noticed the question properly....... sorry
see it's easy...
as if I have already answered the question i can't send u the picture where I have solved it....
make a square marked with P,2P,3P and 4P in order
now u can see that 2P and 4P are directed in opposite direction so there resultant will be 2P and u can even see that P and 3P are in opposite direction their resultant will be 2P as well
now ,
the angle between 2P vector and 2P vector is π/2
so there resultant will be 2√2P
by using,
R = √2P²+2P² + 4P²cos90°
R = √8P²
R= 2√2P
vishagh:
The answer shown is 2 root 2P...shati
sorry friend...... delete my answer......
Thnq shati..se u did it..!! :)
its all bcoz of ur motivation.......but hopefully u understood what I want to say......... I am idiot.... sorry once again
Np...thnq ao much helped.a lot
:-) credit goes to: vishagh
Hahaha..u answered it..!! Thnx for helping
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