Question

Four friends from Delhi hired a taxi to visit Agra (one side road distance 210
km). It travels a distance of 250 km in 25 litres (capacity of fuel tank) of petrol
at an average speed of 48km/hour. They covered a distance of 80 km and spent
4 hours in visiting all the tourist places in and around Agra. The taxi fare is
20 per km. The cost of petrol is10000 per 10 1litres. They started from Delhi
at 6 A.M. and wanted to reach back Delhi before 6 P.M. to avoid extra payment
of 500 per hour.
20 per kmn
SAME DAY
AGRA
Based on this information, answer the following questions:
i) How many litres of petrol will be consumed in the whole trip ?
25 litres (a) (b) 40 litres (c)50 litres (d) 60 litres ​

Answer 1

Answer:

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3 ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)