Question

Four friends go for an evening walk together.
Their paces measure 75 cm, 80 cm and 90 cm
respectively.
Find the minimum distance each should cover to
walk the same distance in complete (whole) paces.​

Answer 1

Answer:

The distance D will be such that D=75P1=80P2=90P3 where P1,P2,P3 are positive integers. So D is divisible by 75,80, and 90. So D is a common multiple of 75,80, and 90. Let E be the least common multiple of 75,80, and 90 Then D≥E. But we can let D=E, and P1=E/75,P2=E/80, and P3=E/90,