Question

Four friends race their bikes down the street. Evan finishes in 6.2 seconds, Devon in 6.0999 seconds, Liza in 6.188 seconds and Tasha in 6.168 seconds. Which order shows the friends' times from fastest to slowest? (6.NS.C.7.A) * 1 point Tasha, Liza, Evan, Davon Evan, Tasha, Liza, Devon Devon, Evan, Tasha, Liza Devon, Tasha, Liza, Evan

Answer 1

Answer:

Look

Step-by-step explanation:

Fastest to slowest

1. Devon

2. Tasha

3. Liza

4. Evon

Like if it's right

Answer 2

The order shows the friends' times from fastest to slowest - Evan Liza Tasha Devon

GIVEN:

Time taken by-

• Evan - 6.2sec
• Devon - 6.0999sec
• Liza- 6.188 sec
• Tasha- 6.168sec.

TO FIND:

Order showing friends' time from fastest to slowest.

SOLUTION:

To arrange the time value from fastest to slowest (in descending order.) we will follow the following steps-

To arrange in descending order- we need to look at the digits from left to right.

The whole number in all the numbers is common = 6.

Now we will look at the tenth place - 6.2, 6.0999, 6.188, 6.168

Digit with tenth place, 2 > 1

So, the biggest number = is 6.2

And, the second biggest number is either 6.188 or 6.168. (As they have the same digit in tenth place)

Comparing the digit in hundredth place between 6.168 and 6.188.

Since 8 > 6

so, the second biggest number - is 6.188.

and the third biggest number = 6.168.

Also, the remaining number - 6.0999 is the lowest.

So the descending order of time values can be written as -

6.2 > 6.188 > 6.168 > 6.0999

Friends' corresponding the orders -

Evan > Liza > Tasha > Devon.

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