Question

Four Friends Ram , Raju ,Ravi Ritu are standing in reference to a well situated at the origin with

the following respective co ordinates ( 2, 4) ( -2 , 4) ( -2 , -4) ( 2 , -4).



1) By plotting the points on a single graph paper, The figure obtained is rectangle, find the

perimeter of the rectangle

a) 12 cm b) 24 cm c) 48 cm d) 8 cm



2) Find the distance between Ram and Raju

a) 2cm b) 3cm c) 4 cm d) 5 cm



3) Raju stands on which quadrant

a) Quadrant I b) Quadrant II c) Quadrant III d) Quadrant IV



4) Ordinate of (2 , -4)

a) -4 b) -2 c) 4 d) 2



5 ) Abscissa of ( -2 , -4 )

a)-4 b ) -2 c) 4 d)2

pls answer fast​

Answer 1

Answer:

idk answer thx for the points

Step-by-step explanation:

Answer 2

Answer:

1) Option (b) 24 cm

2) Option (c) 4 cm

3) Option (b) Quadrant II

4) Option (a) $-4$

5) Option (b) $-2$

Step-by-step explanation:

1) After plotting the points on a single graph paper, the figure obtained is a rectangle.

From the graph,

Length, $AD=8$ units

And width, $CD=4$ units

The perimeter of the rectangle = 2(length + width)

                                                    = $2(8+4)$

                                                    = $2\times 12$

                                                    = $24$ $cm$

Therefore, the perimeter of the rectangle is $24$ cm.

Hence, option (b) is correct.

2) The co-ordinate of the Ram = (2, 4)

And the co-ordinate of the Raju = (-2, 4)

Let $(x_1,y_1)=(2,4)$ and $(x_2,y_2)=(-2,4)$

Using distance formula,

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

               = $\sqrt{(-2-2)^2+(4-4)^2}$

               = $\sqrt{(-4)^2+(0)^2}$

               = $\sqrt{16}$

               = 4 cm

Therefore, the distance between Ram and Raju is 4 cm.

Hence, option (c) is correct.

3) From the graph, Raju stands in the Quadrant II.

Hence, option (b) is correct.

4) Ordinate is the second component of an ordered pair.

Therefore, the ordinate of (2, -4) is $-4$.

Hence, option (a) is correct.

5) Abscissa is the first component of an ordered pair.

Therefore, the Abscissa of (-2, -4) is $-2$.

Hence, option (b) is correct.

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