Question

Four identical charges each charge q are placed at the corners of a square the resultant electric intensity E and the net electric potential V are

Answer 1

Given:

Four identical charges each charge q are placed at the corners of a square  

To find:

The resultant electric intensity E and the net electric potential V are

Solution:

From given, we have,

Four identical charges each charge q are placed at the corners of a square  

The forces are directed towards the corners from the centre.

So, the resultant electric intensity, E₀ = 0

The net electrical potential is given by,

V₀ = 4V

= 4[kq/(d/√2)]   (diagonal of a square d/√2, with the side d)

V₀ = 4√2 (kq/d)

Answer 2

Given that,

Charge = q

Electric intensity = E

Electric potential = V

According to given information,

Electric field at the center will be zero.

$E_{0}=0$

The distance will be$\dfrac{r}{\sqrt{2}}$

We need to calculate the net electric potential

Using formula of electric potential

$V_{0}=4V$

Put the value of V

$V_{0}=4\dfrac{kq}{r}$

Put the value of r into the formula

$V_{0}=4\dfrac{\sqrt{2}kq}{r}$

Hence, The resultant electric intensity E and the net electric potential V are 0 and $4\dfrac{\sqrt{2}kq}{r}$