Four identical electrical lamps are labelled 1.5V, 0.5A which describes the condition necessary for them to operate at normal brightness. A 12V battery of negligible internal resistance is connected to lamps as shown, then
Attachments:
Answers
Answered by
1
Answer:
The value of R normal brightness of each lamp is (3/4)Ω
The value of R(21/4)Ω
Total power dissipated in circuit when all lamps are normally bright is 24W
Power dissipated in R21W
Answer :
B
Solution :
(b) Fro normal brightness of each bulb see following circuit. Current through each bulb =0.5A
i=2A
=1.5V
=10.5V
V=iR⇒10.5=×R=R=214Ω
Explanation:
I hope it will help you
Similar questions
Chemistry,
3 months ago
Computer Science,
3 months ago
Hindi,
7 months ago
Environmental Sciences,
11 months ago
World Languages,
11 months ago
Math,
11 months ago