four identical rods of same material are joined end to end to form a square if the temperature difference between the ends of diagonal is hundred degree Celsius then the temperature difference between the ends of other diagonal will be
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Three conducting rods of same material & area of cross - section are figured as shown . Then , l1l2=?l1l2=?
the temperature of point O be
So , (TA−TO)l1=(TO−TB)l2+(TO−TC)l3(TA−TO)l1=(TO−TB)l2+(TO−TC)l3
10l1=50l2+202l210l1=50l2+202l2
10l1=50l2+10l2=60l210l1=50l2+10l2=60l2
l1l2=16
the temperature of point O be
So , (TA−TO)l1=(TO−TB)l2+(TO−TC)l3(TA−TO)l1=(TO−TB)l2+(TO−TC)l3
10l1=50l2+202l210l1=50l2+202l2
10l1=50l2+10l2=60l210l1=50l2+10l2=60l2
l1l2=16
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