Question

Four identical spheres each of radius 10 cm and
equal mass 1 kg, each are placed on horizontal
surface touching each other so that their centres
are located at the vertices of a square of side 20
cm. What is the distance of their centre of mass
from the centre of either sphere?​

Answer 1

Answer:

Finding CM of both horizontal pair of spheres

And then the CM of the centre of mass will be in the middle to the sphere

Then finding distance of CM(4 kg) from centre of either sphere

Thus distance is

10

2root cm

Answer 2

Answer: 10√2cm

Explanation:

Refer to the attachment. We need to the length of BO. Using Pythagoras Theorem.

BO² = BE² + OE²

BO² = 10² + 10²

BO² = 200

BO = √200

BO = 10√2