Question

four identical taps are opened together can empty a 64 litre tank in 2 hours from the time the first step is opened after every 10 minutes and other tape is opened how much volume in litre of the tank will be left after 2 hours​

Answer 1

Answer:

Therefore time taken by the tap of larger diameter =(x−9)hours

Work done by the tap of smaller diameter in one hour =

x

1

and the work done by the tap of larger diameter in one hour =

x

1

−9

Thus , the work done by the 2 taps together in 1 hour

==

x

1

+

x

1

−9

=x−9+

x

x

(x−9)

=

x(x−9)

2x−9

The 2 tapes together can fill the tank in

2x−9

x(x−9)

According to question

2x−9

x(x−9)

=6hours

x²−21x+54=0

x²−3x−18+54=0

x(x−3)−18(x−3)=0

(x−3)(x−18)=0

Either x−3=0

or x−18=0

Either x=3orx=18

When x = 3, then tap of smaller diameter can fill the tank in 3 hours and the tap of larger diameter can fill the tank in 3 - 9 = -6, which is rejected as a time to fill the tank can't be negative

When x = 18 , then the tap of smaller diameter can fill the tank in 18 hours and the tap of larger diameter can fill the tank in 18−9=9hours.

Step-by-step explanation:

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