Question

Four identical thin rods each of mass M and length l, from a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is :

Answer 1

Answer:

Identical thin rods have the mass M and length l, from a square frame to use the theorem of parallel axes: I = ICM +Ma2 where ICM is the moment of inertia about an axis through the centre of mass of the rod. I is the moment of inertia about a parallel axis at distance a. Moment of inertia is thin rod of mass M and length L about an axis through the mid point of the rod and perpendicular to its length is ML2/12.

Answer 2

Answer:

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