Question

Four identical uniform thin rods, each of mass m and
length / are joined to a common point Q as shown
in the figure. Moment of inertia of the system about
an axis passing through O and lying in the plane of
rods is​

Answer 1

Inertia of rod passing through axis which is perpendicular to its plane is ML^2/12

by perpendicular axis theorem

Iz = Ix + Iy

ML^2/12 = 2 Ix

Ix= ML^2/ 24

Inertia of rod in the plane = ML^2/ 24

For inertia along axis making an angle theta with original axis

I = I' sin^2 theta

I = ML^2 / 24 * sin^2 (60°)

I = ML^2 /24 * 3/4

I = ML^2/ 32

this is for one rod

so for system

I"= 2I

I"= ML^2 / 16

plz mark it Brainliest

thank u..

hope it helps