four integers are added to a group of integers 3,4,5,5,8 and the mean median and mode of data increases by 1 each. what is the greatest integer in the new group of integers?
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Solution:-
The given integers are 3, 4, 5, 5 and 8.
Mean = (3 + 4 + 5 + 5 + 8)/5
= 25/5
Mean = 5
Median = 5
and Mode = 5 (Mode is the most frequently occurring value)
After adding 4 integers, mode is increased by 1,
Therefore, the new mode is 6.
Since, the mode is most frequently occurring value, there 6 must be added at least three times.
So, the new set of integers will be 3, 4, 5, 5, 6, 6, 6, 8 and x.
Let the 4th integers be 'x'.
And the new mean is 6.
6 = (3 + 4 + 5 + 5 + 6 + 6 + 6 + 8 + x)/9
(43 + x)/9 = 6
43 + x = 54
x = 54 - 43
x = 11
So, greatest of the four integers that are added is 11.
Answer.
The given integers are 3, 4, 5, 5 and 8.
Mean = (3 + 4 + 5 + 5 + 8)/5
= 25/5
Mean = 5
Median = 5
and Mode = 5 (Mode is the most frequently occurring value)
After adding 4 integers, mode is increased by 1,
Therefore, the new mode is 6.
Since, the mode is most frequently occurring value, there 6 must be added at least three times.
So, the new set of integers will be 3, 4, 5, 5, 6, 6, 6, 8 and x.
Let the 4th integers be 'x'.
And the new mean is 6.
6 = (3 + 4 + 5 + 5 + 6 + 6 + 6 + 8 + x)/9
(43 + x)/9 = 6
43 + x = 54
x = 54 - 43
x = 11
So, greatest of the four integers that are added is 11.
Answer.
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Step-by-step explanation:
चल निकल पहली फुर्सत में निकल चल पोरिन डीजे सारे ग्रुप इन डिजिट 3 4 5 5 एंड 8 एंड मीन मेडियन एंड मॉड ऑफ द डाटा इंक्रीजस बाय वन इज व्हाट इज द ग्रेटेस्ट इंटिगर हिंदी न्यू ग्रुप विभिन्न सेट ऑफ इंजीनियरिंग 23455 एंड द मीन ऑफ द गिवेन टाटा एजुकेशन ऑफ इंटीरियर बाय नंबर ऑफ इंटीरियर इज इक्वल टू 3 प्लस 4 प्लस 5 प्लस 5 प्लस 8 प्लस टू बाय 5 प्लस रूट 5 इज इक्वल टू फाइंड द मीडियन ऑफ द डाटा 345 5885 345 585 एंड मी y1
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