Question

four masses each of 2kg are placed on a horizontal disc of negligible mass, which can be rotated about a Vertical axis passing through its centre. if all the masses be equidistant from the axis and at distance of 10cm from it, what is moment of inertia of the whole system?​

Answer 1

Answer:

8 * 10⁵ gm cm²

Step-by-step explanation:

MI of system= 4*m*d²

= 4 * (2kg) * (10cm)²

= 4* (2000g) * 100cm²

= 8 * 10⁵ gm cm²

Therefore, the moment of inertia of the whole system is 8 * 10⁵ gm cm²

Hope it helps

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