Question

four men and three women are to be seated for a dinner such that no two women sit together and no two men sit together. find the number of ways in which this can be arranged.

Answer 1

answer is 4! 3! = 24*6 = 144

4! for arranging 4 man in a row first
like

M1 M2 M3 M4

NOW WE can see three gaps b/w men

so we will place 3 women in those 3 gaps by 3!

thus answer 4!*3! = 144 ways

Answer 2

The arrangement will be as follows:-
M , W , M , W , M , W , M

And if the first man and last man are to be seemed together, then place one more chair between them.

Please mark this as the brainliest answer.
GOOD LUCK....