Question

Four moles of a perfect gas heated to incrcrease its temperature by 2°C absorbes heat of 40 cal at
constant volume. If the same gas is beated at constant pressure the amount of heat supplied
is, (R = 2 cal/mol K)​

Answer 1

Answer:

heat at constant volume , U = 40 calorie

or, nCv∆T = 40 calorie

or, 4mol × Cv × 2°C = 40 calorie

or, Cv = 5 Calorie/mol.°C

we know, Cv = R/(1 - Y)

R is universal gas constant. i.e., R = 2 cal/mol.°C

so, 5 = 2/(1 - Y)

or, 5(1 - Y) = 2

or, 5 - 5Y = 2

or, 3 = 5Y

or, Y = 5/3

now, Cp = YR/(1 - Y) = 5/3 × 5 = 25/3 cal/mol.°C

so, heat at constant pressure = nCp∆T

= 4 mol × 25/3 cal/mol.°C × 2 °C

= 200/3 calorie

= 66.67 calorie

Explanation:

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Answer 2

Answer:

Given that,

n=2moles , dU=40cal ,R=cal /mol K , T=2degree C

(dW=nRdT)

Explanation:

dQ=dU=nCpT =40C

dQ=dU+dW

dQ=40+nRdT

dQ=40+4×2×2

dQ=40+16

dQ=56 Kcal

Hope it helps you