four non-negative integers(a1,a2,a3,a4) sum to 101010. no carry is performed while adding these four numbers how many ways you can choose(a1,a2,a3,a4)
Answers
Step-by-step explanation:
write the five negative integer greater than 30
Given : four non-negative integers(a1,a2,a3,a4) sum to 101010.
no carry is performed while adding these four numbers
To Find : how many ways you can choose(a1,a2,a3,a4)
Solution:
no carry is performed Hence numbers must be consist of 1 and 0 only
in largest number initial 1 must be there
and remaining 2 , 1's possible cases are 2 x 2 = 4 ( 1 is there or 0 is there)
100000 , 100010 , 101000 , 101010
incase of 100000 remaining to be added is 1010 Here also 2nd 1 can be there or not hence 2 cases
so total 5 cases
Here are the 5 possible cases
100000 + 1000 + 10 + 0
100000 + 1010 + 0 + 0
100010 + 1000 + 0 + 0
101000 + 10 + 0 + 0
101010 + 0 + 0 + 0
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