Physics, asked by BandaPagaL, 1 year ago

Four nuclei of an element undergo fusion to form a heavier nucleus, with release of energy. Which of the two  the parent or the daughter nucleus  would have higher binding energy per nucleon ?

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Anonymous: hlo

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Answered by MohammedIlyas
0

The daughter nucleus would have the higher binding energy per nucleon.

because:-

*Let BE of each parent be b per nucleon, and let there be N nucleons in each parent.

*Total energy to split the parents would be 4 x b x N.

*Now these parents combine into a daughter by releasing energy E.

*So the total energy to split the daughter would be E + 4 x b x N. So, energy per nucleon would be E/(4N) + b, which is > b, which shows that BE per nucleon of the daughter is greater.

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