Math, asked by saiteja2198, 11 months ago

four number are in arthematic progression the sum of first and last terms is 8 and the product of both middle terms is 15 then the least number of the seris is​

Answers

Answered by vivek4747
6

Answer:

please mark as brainliest

1,3,5,7

or

7,5,3,1

Step-by-step explanation:

let numbers are

a-3d,a-d,a+d,a+3d

A.T.Q.

a-3d+a+3d=8

2a=8

a=4

(a-d)(a+d)=15

a^2-d^2=15

16-d^2=15

d^2=1

d=1,-1

so,

numbers are

4-3d=4-3×1=1

4-d=4-1=3

4+d=4+1=5

4+3d=4+3×1=7

1,3,5,7 when d=1

and

7,5,3,1 when d=-1

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