four number are in arthematic progression the sum of first and last terms is 8 and the product of both middle terms is 15 then the least number of the seris is
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Answer:
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1,3,5,7
or
7,5,3,1
Step-by-step explanation:
let numbers are
a-3d,a-d,a+d,a+3d
A.T.Q.
a-3d+a+3d=8
2a=8
a=4
(a-d)(a+d)=15
a^2-d^2=15
16-d^2=15
d^2=1
d=1,-1
so,
numbers are
4-3d=4-3×1=1
4-d=4-1=3
4+d=4+1=5
4+3d=4+3×1=7
1,3,5,7 when d=1
and
7,5,3,1 when d=-1
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