Question

Four numbers are in A.P. & their
sum is 72 & the largest of them is
twice the smallest then the numbers
are ......​

Answer 1

Answer:

let numbers be a-3d, a-d, a+d and a+3d

then, a-3d+a-d+a+d+a+3d = 72

= 4a = 72

= a = 72/4 = 18

and, a+3d = 2(a-3d)

= a + 3d = 2a - 6d

= a = 9d = 18

= d = 2

so, the numbers are 12 , 16 , 20 , 24

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