Question

four numbers are in A. P. And their sum is 72 and the largest of them is twice the smallest, Then the numbers are............

Answer 1

Answer: 12 , 16 , 20 , 24

Step-by-step explanation:

let numbers be a-3d, a-d, a+d and a+3d

then, a-3d+a-d+a+d+a+3d = 72

= 4a = 72

= a = 72/4 = 18

and, a+3d = 2(a-3d)

= a + 3d = 2a - 6d

= a = 9d = 18

= d = 2

so, the numbers are 12 , 16 , 20 , 24

Please mark as Brainliest

Answer 2

Answer:

d=2

Step-by-step explanation:

AP =a-3d,a-d,a+d and a+3d

4a=72

a=72/4 = 18

a+3d =2a- 6a

d=2